Question

14. In the given figure, ∆ABC is an isosceles triangle in which AB = AC. If AB and AC are produced to D and E, respectively such that BD = CE, prove that BE = CD. ​

Answer 1

Answer:

in triangle ADC & triangle ABE

AD=AE (SINCE AB=AC & CE=BD)

ANGLE DAE IS COMMON

AB = AC (GIVEN)

Therefore triangle ADC is congruent to triangle ABE (SAS)

therefore BE=CD

Step-by-step explanation:

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