Question

14. In the given figure, ABCD is trapezium with AB || DC. The bisectors of ZB
and ZC meet at point O. Find ZBOC.


Please solve in your rough copy​

Answer 1

Answer:

angle BOC=90°

Step-by-step explanation:

ANGLE B + ANGLE C =180°

(angle on the same side of transversel are supplementary as AB//DC)

DIVIDING BY 2 ON BOTH SIDES

ANGLE B/2 + ANGLE C/2 =180°/2

angle OBC + angle OCB = 90°

in triangle OBC

angle OBC + angle OCB +angle BOC =180°

90° + angle BOC =180°

ANGLE BOC = 90°

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Answer 2

Answer:

angle BOC=90

Step-by-step explanation:

we know that the sum of adjacent angles in a parallelogram is 180 degree

therefore, ZB+ZC=180

1/2(ZB+ZC)=90

NOW TO FIND ZBOC

ZBOC+1/2(ZB+ZC)=180

ZBOC+90=180

ZBOC=90

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