14. Prove that vector A (AXB) = 0.
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Answered by
8
Answer:
Let A.(AxB) = 0
As , AxB = AB sinФ n
AB sinФ n is a vector which is perpendicular to the plane having A vector and B vector which implies that it is also perpendicular to A vector .
As we know dot product of two vectors is zero.
Thus , we can say that
A.(AxB) = 0
HENCE PROVED !!
Answered by
2
Answer:
0
Explanation:
A(A×B) =0
A×a×A×b
1×0
=0
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