Math, asked by kaifakar7, 11 months ago


14. Rani walks 3 km south from her house, turns west and walks 4 km. She then turn southward
walks 2 km and then walks 4 km eastward,
How many kms would she have saved had she taken the shortest path?
(a) 2 km
b) 3 km
(c) 8 km
d) 5 km​

Answers

Answered by swaroop91
32

Answer:

5 km because 3km South 4km on west and again 2 km in south and 4 km on east and 4-4=0 so 3+2=5

=5

Answered by orangesquirrel
19

Answer:

The correct answer is (c) 8 km.

Step-by-step explanation:

By following the movements of Rani, we can determine that if she had taken the shortest route,i.e. directly to the south from her initial location then she would have saved 8km.

Adding up all her distances, we get the total distance travelled by her which is 3+4+4+2= 13km.

She could have directly walked 5 km towards south from her initial position to reach the final position.

Hence, the difference between the two distances = (13-5) km = 8km.

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