Question

14. The altitude of a right angle is 7 cm less than its base. If the hypotenuse is 13 cm,
find the other two sides.
​

Answer 1

Answer:

Let x be the base of the triangle,

then the altitude will be (x−7).

By Pythagoras theorem,

x*2+(x−7)*2=(13)*2

2x*2-14x+49-169=0

2x*2-14x-120=0

x*2-7x-60=0

x*2-12x+5x-60=0

x(x-12)+5(x-12)=0

(x-12)(x+5)=0

x=12,x=-5

Since the side of the triangle cannot be negative, so the base of the triangle is 12cm and the altitude of the triangle will be 12−7=5cm.

Answer 2

Answer:

answer

Step-by-step explanation:

By Pythagoras theorem ,

x* + ( x -7 )* = ( 13 )*

2x* - 14x + 49 - 169 = 0

2x* - 14x -120 = 0

x* - 7x -60 = 0

x*- 12x + 5x - 60 = 0

( x - 12 ) ( x + 5 ) = 0

Therefore x = 12 and x = -5