14. The energy of an a-particle is 6-8 x 10-18 J. What
will be the wavelength associated with it?
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Explanation:
Using the De-Broglie's equation
E=6.8×10
−18
J
λ=
mv
h
⇒λ
2
=
(2×
2
1
m
2
v
2
)
h
2
⇒λ=
2Em
h
λ=
2×6.8×10
−18
×4×1.66×10
−27
6.626×10
−34
λ=2.2×10
−12
m
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