14. The product of (2a+3b) X 5a X 0 is
(a) 10a2+15ab (b) 5a (c) 2a+3b d ) 0
Answers
Question :- the product of (2a+3b)×5a×0 is ?
(a) 10a2+15ab
(b) 5a
(c) 2a+3b
(d) 0
Solution :-
→ (2a + 3b) * 5a * 0
→ (2a * 5a + 3b * 5a) * 0
→ (10a² + 15ab) * 0
now, we know that, when any number is multiplied with Zero, it gives result as Zero.
therefore,
→ (10a² + 15ab) * 0
→ 0 = Zero (Ans.d)
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Given:
(2a+3b) ×5a×0
To find:
The product
Solution:
(2a+3b) ×5a×0
=> (2a+3b) x 0
when we multiply any number with 0 the result will always a 0.
Using distributive property (a+b)xc = axc + bxc
=> 2ax0 + 3bx0
=> 0 + 0
=> 0
Hence, (2a+3b) ×5a×0 = 0