Physics, asked by sk4921671, 6 months ago

14 Three identical smooth cylinders each of mass √3 kg are
placed as shown in the figure. Find normal reaction
between cylinder A and cylinder B
. 10 N
b 20 N
103N
Cannot be calculated

Answers

Answered by yashdubey21092004
1

Answer:

Let normal reaction between cylinder A and B be N.

2Nsin60°=mg

2n \times  \sqrt{3}  \div 2 =   \sqrt{3}  \times 10

N=10N

Similar questions