Math, asked by mrsanjiv83, 11 months ago

14. Three pipes A, B and C can fill a tank in 30 mins 20 minutes and 10 minutes
respectively. When the tank is empty, all the three pipes are opened. A. B and C discharge
chemical solutions P. Q and R respectively, what is the proportion of solution R in the liquid
in the tank after 3 minutes?
laj 5
6
(b)
11
11 t
id​

Answers

Answered by Anonymous
1

Answer:

Part filled by (A + B + C) in 3 minutes = 3 1/30 + 1/20 + 1/10 = 3 x 11/60 = 11/20

When c works for 1 min its work done in 1 min = 1/10

so when it works for 3 min its contribution = 3/10

Required ratio = 3/10 x 20 /11= 6 /11..

hope this will help you........

Answered by gothwalshubham95
2

If you try to solve it using LCM method, it will be much easier.

Mark as the brainliest if you like :)

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