Question

14. Two baskets contain 195 and 250 bananas
respectively, which distributed in equal number among
children. Find the largest number of bananas that can be
given, so that 3 bananas are left over from the first basket
and 2 from the second.
1)4
2)18
3)8
4)6
pls tell me the procedure.....​

Answer 1

Answer:

Answer is 8 correct

Step-by-step explanation:

195-3=192

250-2=248

192=2×2×2×2×2×2×3

248=2×2×2×31

so, the H.C.F= 2×2×2=8

Answer 2

The largest number of bananas is 8.

Given:

Bananas in first basket = 195

Bananas in second basket = 250

Bananas left over in the first basket = 3

Bananas left over in the second basket = 2

To Find:

The largest number of bananas that can be given

Solution:

Since from the first basket 3 bananas are left over -

Therefore,

195 - 3

= 192

Similarly,

Since from the first basket 3 bananas are left over -

Therefore,

250 - 2

= 248

Finding the divisors of both -

192

= 2 × 2 × 2 × 2 × 2 × 2 × 3

248

= 2 × 2 × 2 × 31

H.C.F of both the numbers

= 2 × 2 × 2

= 8

Answer: The largest number of bananas that can be given is 8

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