Question

a car accelerates uniformly at the rate of 2m/s after starting from rest . find the distance travelled and the velocity attained in 4 sec​

Answer 1

since car is accrelerating at 2m/s then after 4 sec its velocity will be 2m/s ×4sec=8m/s and distance is given by second equaton of motion:

ut + 1/2at^= 0×4 + 1/2 × 2 ×4^=16m

Answer 2

Answer:

answer is 8m/s

Explanation:

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