Physics, asked by shillythegreat, 4 days ago

14.Two resistors of 2ohm and 3ohm are connected in parallel to a cell of emf 2V.Calculate the main current passing through the circuit and current through individuals resistors.​

Answers

Answered by jatinjattu0
0

Answer:

Two resistors of resistance 2Ω and 3Ω are connected in parallel with p.d. of 2V

Net current passing through the circuit

Current passing through both resistors

⏭ Formula:

Formula of equivalent resistance in parallel connection is given by...

1/Req= 1/R1+1/R2

→ As per ohm's law relation between potential difference, current flow and resistance is given by...

V=I*R

⏭ Calculation:

_________________________________

Equivalent resistance

1/Req=1/2+1/3

1/Req+3+2/6

Req=5/6ohm

_________________________________

Net current passing in the circuit

v=Inet×Req

2=1net×6/5

Inet=5×2/6

Inet = 10/6

Inet=1.67A

_________________________________

Current in 2Ω resistor

v=I×R

2=I×2

I=1A

_________________________________

Current in 3Ω resistor V

V=I'×R

2=I'×3

I'=0.67A

Explanation:

Answered by ishajangid2003
0

Answer:

main current passing through the circuit I =5/3 amp.

current through individuals resistors;

I1 =1amp.

I2=2/3amp.

Explanation:

main current passing through the curcuit;

1/R=1/R1+1/R2

=1/2+1/3

=5/6

R. =6/5

Current through individuals resistors;

I1 =V/R1

=2/2

I1 =1 A

I2=V/R2

I2=2/3 A

Similar questions