14.Two resistors of 2ohm and 3ohm are connected in parallel to a cell of emf 2V.Calculate the main current passing through the circuit and current through individuals resistors.
Answers
Answer:
Two resistors of resistance 2Ω and 3Ω are connected in parallel with p.d. of 2V
Net current passing through the circuit
Current passing through both resistors
⏭ Formula:
Formula of equivalent resistance in parallel connection is given by...
1/Req= 1/R1+1/R2
→ As per ohm's law relation between potential difference, current flow and resistance is given by...
V=I*R
⏭ Calculation:
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Equivalent resistance
1/Req=1/2+1/3
1/Req+3+2/6
Req=5/6ohm
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Net current passing in the circuit
v=Inet×Req
2=1net×6/5
Inet=5×2/6
Inet = 10/6
Inet=1.67A
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Current in 2Ω resistor
v=I×R
2=I×2
I=1A
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Current in 3Ω resistor V
V=I'×R
2=I'×3
I'=0.67A
Explanation:
Answer:
main current passing through the circuit I =5/3 amp.
current through individuals resistors;
I1 =1amp.
I2=2/3amp.
Explanation:
main current passing through the curcuit;
1/R=1/R1+1/R2
=1/2+1/3
=5/6
R. =6/5
Current through individuals resistors;
I1 =V/R1
=2/2
I1 =1 A
I2=V/R2
I2=2/3 A