Question

14. What value of a would make the given
quadrilateral a parallelogram?
(a) 4
(6 6
(b) 5
(d) 8​

Answer 1

As the diagonal of quadrilateral bisects each other; 5b-4=3b+6
2b=10
b=5
So by the same rule;3b-4=2a
15-4=2a
11=2a
a=
2
11
​

Answer 2

Answer:

(d)8

Step-by-step explanation:

as we know diagonals of parallelogram bisect each other

thus,3b-2=2a and 3b+3=5b-9

3b-2a=2-----(1)

3+9=5b-3b

12=2b

b=6---(2)

Substituting b=6 in equation(1),

3(6)-2a=2

18-2=2a

16=2a

a=8---(3)

Thus,value of a is 8 for the given quadrilateral to be a parallelogram.