14 x + 10 y =33, kx + 5y = 11 find the value of k
Answers
Answer:
Step-by-step explanation:
CONDITION FOR PARALLEL LINES
A1/A2=B1/B2
HERE
A1=14,A2=K
B1=10,B2=5
THEN,
14/K=10/5
K=7
Value of k is (14x-11)/2x
Step-by-step explanation:
14 x + 10 y =33 ................ Eq. No. 1
kx + 5y = 11 .................... Eq. No. 2
on multiplying eq. no. 2 by 2 and then on subtracting, we get:
14 x + 10 y =33
2kx + 10y = 22
-----------------------
(14x-2kx) + 0 = 11
14x-11 = 2kx
k = (14x-11)/2x
Know More:
Q.1. X^x^x^x^x^x.......=2 then x=?
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Q.2. #x-1/x=4 So,prove that (x×x×x×x×x×x×x×x)+1=194×(x×x×x×x)
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Value of k is (14x-11)/2x
Step-by-step explanation:
14 x + 10 y =33 ................ Eq. No. 1
kx + 5y = 11 .................... Eq. No. 2
on multiplying eq. no. 2 by 2 and then on subtracting, we get:
14 x + 10 y =33
2kx + 10y = 22
-----------------------
(14x-2kx) + 0 = 11
14x-11 = 2kx
k = (14x-11)/2x
Know More:
Q.1. X^x^x^x^x^x.......=2 then x=?
Click Here: https://brainly.in/question/1806834
Q.2. #x-1/x=4 So,prove that (x×x×x×x×x×x×x×x)+1=194×(x×x×x×x)
Click Here: https://brainly.in/question/3161337