Question

142. The sides of a triangle containing the right
angle are 5x cm and (3x-1) cm. If the area of
the triangle is 60 cm, calculate the lengths of
these two sides of the triangle.
10​

Answer 1

$\huge\mathfrak {Solution:-}$

The sides of a right triangle containing the right angle are (5x) cm and (3x-1) cm.  

Area of triangle = 60°

$\sf {\frac{1}{2}\times (5x)(3x-1) = 60\ degrees}$

$\sf {Solving\ this\ we\ get\ x\ = 3\ or\ x = \frac{-3}{8} }$

$\sf {As\ x\ is\ unequal\ to\ \frac{-3}{8}\ hence\ x\ = 3}$

The sides of a triangle are 15 cm and 8 cm.

Find hypotenuse of a triangle using Pythagoras we get 17 cm.

Answer 2

The sides of a right triangle containing the right angle are (5x) cm and (3x-1) cm.

Area of triangle = 60°

\sf {\frac{1}{2}\times (5x)(3x-1) = 60\ degrees}

2

1

×(5x)(3x−1)=60 degrees

\sf {Solving\ this\ we\ get\ x\ = 3\ or\ x = \frac{-3}{8} }Solving this we get x =3 or x=

8

−3

\sf {As\ x\ is\ unequal\ to\ \frac{-3}{8}\ hence\ x\ = 3}As x is unequal to

8

−3

hence x =3

The sides of a triangle are 15 cm and 8 cm.

Find hypotenuse of a triangle using Pythagoras we get 17 cm.