145. An arrangement of three parallel straight wiresplaced perpendicular to plane of paper carrying samecurrent ‘I’ along the same direction is shown in Fig.Magnitude of force per unit length on the middle wire‘B’ is given by
(1) μ₀i²/2πd (2) 2μ₀i²/πd
(3) √(2) μ₀i²/πd (4) μ₀i²/√(2) πd
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The magnitude of force per unit length on the middle wire‘B’ is given by
F = μoI^2 / √2πd
Option (D) is correct.
Explanation:
Force between BC and AB will be same in magnitude.
F(BC) = F (BA) = μoI^2 / 2πd
F = √2 F(BC)
F = √2 μoI^2 / 2πd
F = μoI^2 / √2πd
Thus the magnitude of force per unit length on the middle wire‘B’ is given by
F = μoI^2 / √2πd
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