Question

the area of a rectangle in square feet is X square (x2) + 13X +36. HOW MUCH LONGER IS THE LENGTH THAN THE WIDTH OF A RECTANGLE?

Answer 1

Answer:

$Area \: of \: rectangle = {x}^{2} + 13x + 36 \\ = {x}^{2} + 9x + 4x + 36 \\ = x(x + 9) + 4(x + 9) \\ = (x + 9)(x + 4) \\ </p><p>Length = x + 9 \\ </p><p>Breadth = x + 4 \\ difference \: = x + 9 - x - 4 = 5$

Answer 2

Answer:

x = -4,-9

Step-by-step explanation:

x² + 13x + 36

=x² + (9 + 4)x + 36

=x² + 9x + 4x + 36

=x(x + 9) + 4(x + 9)

=(x + 9) (x + 4)

or, x = -9

x = -4

so the value of x = -4,-9