Question

Q. 33. In figure the line segment XY is parallel to side AC of A ABC and it divides the triangle in
to two parts of equal areas. Find the ratio AX/AB​

Answer 1

Step-by-step explanation:

2 Area (xy) = Area (ABC)

In ΔABC & ΔXBY

∠ABC=∠XBY(common)

∠ACB=∠XYB (since XY||AC, angles are equal)

ΔABC∼ΔXBY (AA similarity)

(XBAB)2=Area(ΔBXY)Area(ΔABC)=2

(AB)2=2(XB)2    AB=2×B

AX=AB−XB=AB−2AB=(22−1)AB

ABAX=22−1