Question

148/x+231/y=527/xy ; 231/x+148/y=610/xy Solve the simultaneous equation

Answer 1

Solution:-

given by:-
$\frac{148}{x} + \frac{231}{y} = \frac{527}{xy} \\ 231x + 148y = 527...............(1) \\ \frac{231}{x} + \frac{148}{y} = \frac{610}{xy} \\ 148x + 231y = 610................(2) \\ multipy \: eq(1)with148 \: and \: eq(2) \: with \: 231. \\ 31488x + 21904y = 77996............(3) \\ 31488x + 53361y = 140910..........(4) \\ substrac \: eq(3) \: from \: eq(4) \\ we \: have \\ 31488x + 53361y = 140910 \\ 31488x + 21904y = 77996$
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$31457y = 62914 \\ y = 2 \\ put \: y = 2 \: in \: eq(1) \\ 231x - 148 \times 2 = 527 \\ 231x = 527 - 296 \\ x = \frac{231}{231} \\ x = 1$
here , ( x , y ) = ( 1, 2)

■I HOPE ITS HELP■

Answer 2

148/x + 231/y = 527/xy
(148y + 231x)/xy = 527/xy
148y + 231x = 527-----------( 1 )

231/x + 148/y = 610/xy

(231y + 148x)/xy = 610/xy

231y + 148x = 610------------( 2 )

adding---------( 1 ) & -----------( 2 )

231x + 148y = 527
148x + 231y = 610
---------------------------
379x + 379y = 1137

x + y = 3-----------( 3 )


subtracting-------( 1 ) &-----( 2 )

231x + 148y = 527
148x + 231y = 610
--------------------------
83x - 83y = -83

x - y = -1------------( 4 )

From-------( 3 )&-------( 4 )

x + y = 3
x - y = -1
------------
2x = 2

x = 1 [ put in -----( 3 )]

1 + y = 3

y = 2