Question

15/11 times ₹363. please answer fast​

Answer 1

Answer:

Let the three consecutive multiples of 11 be 11x , 11(x + 1) and 11(x + 2)

 So, 11x + 11x + 11 + 11x + 22 = 363

 or, 33x = 363 - 33

 or, 33x = 330 

 or, x = 10

∴ The multiples are:

11x = 110

11(x+1)= 121

11( x + 2) = 132

Step-by-step explanation:

Answer 2

Answer:

may this answer help you