Math, asked by wolfev4712, 1 month ago

15 ( 2-y ) - 5 ( y+6 ) / 1-3y = 10

Answers

Answered by sahajvirk16
13

Answer:

y=10

Step-by-step explanation:

15 (2-y) -5 (y+6) / 1-3y = 10

30 - 15y -5y + 30 / 1-3y = 10

30 - 20y + 30 / 1-3y = 10

-20y +30/1-3y = 10 - 30

(-20 is common at both side so it will be cancelled out)

-20y + 30= -20 × 3y

30 = 3y

y = 30/3

y = 10

Answered by MrHyper
878

To Find :

  • The value of y in the equation :

 \sf  \bigstar \:   \:   \underline{\boxed{ \sf \dfrac{15(2 - y) - 5(y + 6)}{1 - 3y}  = 10}}

Solution :

\sf{~~~~~~~~~~ {\dfrac{15(2-y)-5(y+6)}{1-3y}}=10}

\sf\implies{{\dfrac{{\cancel{30}}~-15y-5y~{\cancel{-30}}}{1-3y}}=10}

\sf\implies{{\dfrac{-20y}{1-3y}}=10}

\sf\implies{-20y=10(1-3y)}

\sf\implies{-20y=10-30y}

\sf\implies{30y-20y=10}

\sf\implies{10y=10}

\sf\implies{y={\dfrac{10}{10}}}

\sf\implies{{\underline{\boxed{\sf{\pmb{y=1}}}}}}

∴ Required answer :

  • \sf{{\underline{\underline{\sf{\pmb{y=1}}}}}}
Similar questions