Question

15(2-y)-5(y+6)=10/1-3y

Answer 1

15 ( 2 - y ) - 5 ( y + 6 ) / 1 - 3y = 10

30 - 15y - 5y - 30 / 1 - 3y = 10

By cross multiplication -

10 ( 1 - 3y ) = 30 - 15y - 5y -30

10 - 30y = 30 - 15y - 5y - 30

10 - 30 + 30 = -15y -5y + 30y

10 = 10y

y = 10 / 10

y = 1 / 1

y = 1

Therefore y = 1.

Answer 2

15 (2-y) -5 (y+6) = 10/1-3y
=> 15 (2-y) -5 (y+6) = 10 (1-3y)
Multiplying outer digit with inner once
=> 30 - 15y -5y -30 = 10 - 30y
=> -15y - 5y = 10 - 30y
=> -15y - 5y + 30y = 10
=> -20y + 30y = 10
=> 10y = 10
=> y = 10/10 = 1
So the value of y is 1.