Question

15. (2a + 3b)^2 - 4c^2 factorise this​

Answer 1

Answer:

${(2a + 3b)}^{2} - {4c}^{2} \\ \\ 4 {a}^{2} + 9 {b}^{2} - 16 {c}^{2}$

Step-by-step explanation:

I hope this helps u

Answer 2

Answer:

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Factorise

(2a + 3b)^2 - 4c^2

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(a)^2-(b)^2=(a+b)(a-b)

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$(2a + 3b)^2 - 4c^2\\</h2><h2>=>(2a+3b)^2-(2c)^2\\</h2><h2>=>(2a+3b-2c)(2a+3b+2c)$