15. A alone can do a piece of work in 6 days and B alone in 8 days. A and
B undertook to do it for Rs. 3200. With the help of C, they completed the
work in 3 days. How much is to be paid to C?
(a) Rs. 375 (b) Rs. 400 (C) Rs. 600 (d) Rs. 800
Answers
Answer:
Rs.400 is paid to C.
Step-by-step explanation:
Given:- A independently can finish a task in 6 days, while B alone takes 8 days. For Rs. 3200, A and B agreed to perform the task. They finished the job in 3 days with C's aid.
To Find:- How much is to be paid to C ?
Solution:-
→ LCM of 6, 8, and 3 is 24 units
Let the total work be 24 units.
So,
→ The Efficiency of A is calculated as total work/days = 24/6 = 4 units/day.
→ Efficiency of B = Total work / days = 24/8 = 3 units/day.
→ Efficiency of (A+B+C) = Total work / days = 24/3 = 8 units/day.
then,
→ Efficiency of C = Efficiency of (A+B+C) - Efficiency of A - Efficiency of B = 8 - 4 - 3 = 8 - 7 = 1 units/day.
we can conclude that,
The payment was given in the ratio of their Efficiency.
Therefore,
→ C received = = Rs.400 (Ans.)
Hence, Rs.400 is paid to C.
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The correct option is (b) Rs.400 is paid to C.
GIVEN:-
- A independently can finish a task in 6 days
- B alone takes 8 days.
- For Rs. 3200, A and B agreed to perform the task
- They finished the job in 3 days with C's aid.
TO FIND:- How much is to be paid to C
SOLUTION:-
- LCM of 6, 8, and 3 is 24 units
- Let the total work be 24 units.
According to the question,
The Efficiency of A = total work/days = 24/6 = 4 units/day.
The Efficiency of B = Total work/days = 24/8 = 3 units/day.
The Efficiency of A, B and C = Total work/days = 24/3 = 8 units/day.
Accordingly,
The efficiency of C = Efficiency of (A+B+C) - Efficiency of A - Efficiency of B
The payment was given in the ratio of their Efficiency.
Thus, C received = 1/8 × 3200 = Rs 400
Hence, the correct option is (b) Rs.400 is paid to C.
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