Physics, asked by ramashishy040, 10 months ago

15. A Carnot engine takes 6000 cal of heat from a reservoir at 627°C and gives it to a sink at 27°C. The work
done by the engine is
(1) 2 kcal
(2) 3 kcal
☺ 4 kcal
(4) 8 kcal​

Answers

Answered by knjroopa
28

Explanation:

Given A Carnot engine takes 6000 cal of heat from a reservoir at 627°C and gives it to a sink at 27°C. The work  done by the engine is

  • T1 = 627 + 273 = 900 K
  • Q1 = 6 x 10^3 cal
  • T 2 = 27 + 273 = 300 K
  • From Carnot theorem we get
  • Q1 / T1 = Q2 / T2
  • Q 2 = T2/ T1 x Q1
  • Q2 = 300 / 900 x 6 x 10^3
  •      = 2 x 10^3 cal
  • Work done = Q1 – Q2
  •                  = 6 x 10^3 – 2 x 10^3
  •                   = 3 x 10^3 cal
  •                   = 3 K cal
  •                  = 3  x 4.2 x 10^3
  •                   = 12.6 x 10^3 J
Answered by ipsit25
0

Explanation:

answer answer is 12.6 into 10 to the power 6 Joule

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