Math, asked by Mrperfect541, 2 months ago

15. A floor is 45m long and 15m broad .It is covered with tiles each measuring
50cm by 30cm .Find the number of tiles required to cover the floor.

Answers

Answered by Anonymous
5

Answer:

Floor?

Length =40m=40*100=4000

Breadth==15*100=1500

Area =4000*1500=6000000

Tiles,

Length=60cm

Width=50

Area=50*60=3000cm

No of tiles required=6000000/3000=2000

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Answered by DynamiteAshu
4

Answer:

Given below are the dimensions of floor,

Length = 40 m.

Breadth = 15 m.

We know that,

Area = l∗b = 40∗15 = 600{m}^ {2}

.

Here the length of one tile = 60 cm = 6/10 m.

Breadth of one tile = 50 cm = 5/10 m.

So the area of one tile = 6/10∗5/10

= 30/100

= 3/10{m}^{2}

We know that,

Number of tiles = total area of floor / area of one tile,

Substituting the values,

=600/3/10

=(600∗10)/3

=2000.

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