Question

15. A galvanometer of resistance 100 ohm gives f.s.d, with a current of 2 mA. How would u
use it to measure a voltage upto 5 volt ? what will be the meter current when it measure
3 volt?​

Answer 1

Answer:

Explanation:the answer is explained in the attached picture

Answer 2

Answer:

Let a resistance R is used in series of galvanometre.

R effective=R+100

V/I=R+100

5/0.002=R+100

2500=R+100

R=2400 ohm

Other part,

I=3/2500 amp