Question

15. A particle accelerates from rest at a constant rate for
some time and attains a velocity of 8 m/s. Afterwards
it decelerates with the constant rate and comes to
rest. If the total time taken is 4 second, the distance
travelled is
(a) 4 m
(b) 16 m
(d) noneofthe above
(c) 32 m​

Answer 1

Answer:

16m

Explanation:

use v =u +at, u=0 t=4sec given

then apply s=ut+1/2at^2

Answer 2

Answer:

16m

Explanation:

use v =u +at, u=0 t=4sec given

then apply s=ut+1/2at^2