Calculate the resistance of 60 m length the wire having area 0.00000002 sq m and having resistivity 0.00000035 ohm meter
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Heya!!
Given : p(rho) = 0.00000035 ohm.m
l(length of wire) = 60m and A(area) = 0.00000002 m^2
Since R = p*l/A
=) R = 0.00000035 * 60 / 0.00000002 ohm
= 35/10^8 * 60 * 10^8/ 2 ohms
= 1050 ohms.
Hope it helps uh!!
Given : p(rho) = 0.00000035 ohm.m
l(length of wire) = 60m and A(area) = 0.00000002 m^2
Since R = p*l/A
=) R = 0.00000035 * 60 / 0.00000002 ohm
= 35/10^8 * 60 * 10^8/ 2 ohms
= 1050 ohms.
Hope it helps uh!!
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