Question

15. A plane of mass 500kg rises with a vertical acceleration of 10m/s . The weight of the pilot is 60kg. Give the
magnitude and direction of
(a)Force on the floor by the pilot
(b)Force on the helicopter due to the surrounding air (g=10m/s)​

Answer 1

Explanation:

1)force on the floor by pilot is

F = m(a+g)

that is f = 60(10+10)=1200 Newton

2)F =m(a+g)

so f= 560 ( 10+10)=11200 Newton

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Answer 2

Force on the floor by the pilot is 1200 N

Force on the helicopter due to the surrounding air is 11200 N

Explanation:

Given that,

Mas of the plane, m = 500 kg

Acceleration of the plane, $a=10\ m/s^2$

Mass of the pilot, m' = 60 kg

(a) The force on the floor by pilot is  given by :

$F = m'(a+g)\\\\F = 60\times (10+10)\\\\F=1200\ N$

(b) Force on the helicopter due to the surrounding air is given by :

$F=(m+m')(a+g)\\\\F=560\times (10+10)\\\\F=11200\ N$

Hence, this is the required solution.

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