Question

15. A Pythagorean triplet
whose one of the number
is 48:​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Members of pythogorean triplet are 2m, m2 + 1, m2 - 1

smallest member = 2m = 48

m = 24

m2 + 1 = 242 +1

= 577

m2 - 1 = 242 -1

= 575

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Answer 2

Answer:

14,48,50

Step-by-step explanation:

Pythagorean triplets:

For any natural number m > 1, we have (2m) ² + (m^2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

Let m^2-1=48 then m^2=49 => m=7

2m = 14 and m^2+1= 50.

Therefore the Pythagorean triplet is 14,48,50.

Verification:

14^2 + 48^2 = 196 + 2304 = 2500 = 50^2