15 (a³b²c²– a²b³c²+ a²b²c³) ÷ 3abc, Divide the given polynomial by the given monomia
Answers
Answered by
3
given question answer is 5abc(a-b+c)
Answered by
11
Solution :
15( a³b²c² - a²b³c² + a²b²c³ ) ÷ 3abc
= [ 3×5abc(a²bc - ab²c + abc² ]/3abc
After cancellation , we get
= 5( a²bc - ab²c + abc² )
•••
15( a³b²c² - a²b³c² + a²b²c³ ) ÷ 3abc
= [ 3×5abc(a²bc - ab²c + abc² ]/3abc
After cancellation , we get
= 5( a²bc - ab²c + abc² )
•••
Similar questions