Question

15: Calculate the frequency of the spectral line corresponding to n1, = 2 and n2 = 4.
spectral series does this line belong?​

Answer 1

Answer:

Most light is polychromatic and contains light of many wavelengths. ... Part of the explanation is provided by Planck's equation: the ... of the visible lines in the emission spectrum of hydrogen (with n 1 = 2, n 2 = 3, 4, 5,…).

Explanation:

Answer 2

Answer:

First we calculate energy

$E = 13.6( \frac{1}{ {n_1}^{2} } - \frac{1}{n_2 {}^{2} } ) \: eV\\ \\ E = 13.6( \frac{1}{4} - \frac{1}{16} ) \\ \\ E= 13.6 \times \frac{3}{16} \: ev$

Now

$e = h \nu \\ \\ \nu = \frac{E}{h} \\ \\ h = 6.63 \times {10}^{ - 34} Js \\ 1ev = 1.6 \times {10}^{ - 19} \: J$

So

$\nu = \frac{13.6 \times 1.6 \times {10}^{ - 19} }{6.63 \times {10}^{ - 34} } \times \frac{3}{16} \: Hz \\ \\ \nu = 6.15 \times {10}^{15} \: Hz$