15 cot A =8 then (1+sin A)(1-sin A)/(1+cos A)(1-cos A)
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Answered by
2
Answer:
15cotA=8. (given)
cotA =8/15
cotA=base/perpendicular
let base =8k and perpendicular=15k
By PGT
(8k)2+(15k) 2=hypotenuse2
64k2(2 represent square) +225k2
289k2
hypotenuse =17k
SinA=perpendicular/hypotenuse 15/17
cosA =base/hypotenuse=5/17
- (1+sinA)/(1-sinA)
=(1+15/17)/(1-15/17)
( 17+15)17/(17-15)/17
(32/17)/(2/17)
16
krishna5555888756:
sorry I have read wrong answer but it is correct till the value of sinA and cosA
Answered by
4
Answer:
Step-by-step explanation:
15cotA=8. (given)
cotA =8/15
cotA=base/perpendicular
let base =8k and perpendicular=15k
By PGT
(8k)2+(15k) 2=hypotenuse2
64k2(2 represent square) +225k2
289k2
hypotenuse =17k
SinA=perpendicular/hypotenuse 15/17
cosA =base/hypotenuse=5/17
(1+sinA)/(1-sinA)
=(1+15/17)/(1-15/17)
solve and ur answer is 16
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