Math, asked by itzsehaj, 12 hours ago

15. Deepak’s present age is one-third his mother’s present age. If the mother’s age was five times his age 6 years ago, what are their present ages?
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Answers

Answered by shloksonawane33
2

Answer:

Deepak's age is 15 and his mother's age is 45

Step-by-step explanation:

= 1/3 - ? = 1/5

= 1/3 - 1/5 = ?

= 5/15 - 3/15 = ?

= 5/15 - 3/15 = 2/15

So, 2/15 is considered as 6

Then, 1/15 = 3

5/15 = 3 * 5 = 15 is Deepak's age

15 * 3 = 45 is his mother's age

Answered by OoAryanKingoO78
5

Answer:

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Let's take age of deepak now = x

so, his mother's age = 3x

6 years ago ,

Deepak's age =x - 6

Mother's age = 3x -n6

\begin{gathered}5(x - 6) = 3x - 6 \\ 5x - 30 = 3x -6 \\ 5x = 3x - 6 + 30 \\ 5x = 3x + 24 \\ 5x - 3x = 24 \\ 2x = 24 \\ x = \frac{24}{2} = 12\end{gathered}

Age of deepak now = 12

Mother's age now = 3×12

= 36

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