Question

15. Find all the zeros of the polynomial 2x4 - 11x3 + 7x2 + 13x - 7 it being
given that two of its zeros are (3 + 2) and (3-2).​

Answer 1

Answer:

Let f(x)=2x

4

−11x

3

+7x

2

+13x−7

Given : (3+

2

) and (3−

2

) are the zeroes of f(x)

So (x−(3+

2

)) and (x−(3−

2

)) are factors of f(x)

and (x−(3+

2

))(x−(3−

2

))=x

2

−6x+7 is a factor of f(x)

Divide f(x) by x

2

−6x+7 we get

set f(x)=0

2x

4

−11x

3

+7x

2

+13x−7=0

(x

2

−6x+7)(2x

2

+x−1)=0

(x−(3−(

2

))(x−(3+

2

))(2x−1)(x+1)=0

x=3−

2

or x=3+

2

or x=

2

1

or x=−1

hence all the zeros of the given polynomial are (−3−

2

),(−3+

2

),

2

1

and−1.

solution

Step-by-step explanation:

mark me as the brilliantest answer to the