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It is a Question from 10th Class book
CHAPTER-3 (polynomial)
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okay so here's ur answer with attachment ❤️
brainliest plz
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Answer:
I) k=1
II)k=6
Step-by-step explanation:
I)Kx^2+2x+1=0
They have real and distinct roots
-b^2+4ac=0
Here, a=k,b=2,c=1
-4+4(1)(k)=0
-4+4k=0
4k=4
K=1
II) x^2+kx+9=0
They have real and distinct roots
-b^2+4ac=0
Here,a=1,b=-k,c=9
-(-k^2)+4(1)(9)=0
-k^2+36=0
-k^2=-36
k^2=36
k=6
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