Math, asked by sunamiagarwal, 5 months ago

pls...no SPAM
It is a Question from 10th Class book
CHAPTER-3 (polynomial)

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Answers

Answered by arpitravi34
3

okay so here's ur answer with attachment ❤️

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Answered by graceblue
1

Answer:

I) k=1

II)k=6

Step-by-step explanation:

I)Kx^2+2x+1=0

They have real and distinct roots

-b^2+4ac=0

Here, a=k,b=2,c=1

-4+4(1)(k)=0

-4+4k=0

4k=4

K=1

II) x^2+kx+9=0

They have real and distinct roots

-b^2+4ac=0

Here,a=1,b=-k,c=9

-(-k^2)+4(1)(9)=0

-k^2+36=0

-k^2=-36

k^2=36

k=6

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