Question

15. Find the zeroes of the quadratic polynomial x 2 + 19 x + 90

Answer 1

${x \: }^{2} \: + 19x + 90. = {x + 9x + 10}x + 90. = 2 (x + 9) + 10(x + 9). = (x + 9)(x + 10).zeroes \: are \: - 9 \: and \: - 10.$