Question

15. For an n-digit number where n is odd, the number of digits in its square
root are =
(a)
(b) + 1
(c)";
(d) None​

Answer 1

Answer:

For an n-digit number where n is odd, the number of digits in its squareroot are =(a)(b) + 1(c)";(d) None Get the ... ·