Question

15) For what value of k 2k, k+10,3k+2 are in AR.​

Answer 1

Answer:

K+10+2K+3K+2=0

6K+12=0

6K=-12

K=-12/6

K=-2

Answer 2

Hey there!

When three numbers are in A.P, let them be a , b,c. then,

b-a = c -b

2b  = a + c

Applying this we can find value of k.

2b = a + c

2 ( k + 10) = 2k + 3k + 2

2k + 20 = 5k + 2

2k - 5k = 2 - 20

- 3k = - 18  

k = -18 / -3

k = 6

Hope It Helps You!