Question

15.
If a ray of light parallel to principle axis incident on a concave mirror at angle of incidence 37. If reflected ray
meets the principle axis at point B. Find distance of B from pole of mirror :-
1. 3R/8
2.5R/8
3. R/2
4. 3R/4​

Answer 1

Answer:

Explanation:

This is the answer it will help u

Answer 2

Answer:

1. 3R/8

Explanation:

Let $d_{1}$ be distance of point B from pole of mirror

Let R be the radius of Curvature and x be the incident angle

and $d_{2}$ be the distance of center of curvature from point B

Therefore                       $\frac{d_{2}}{sinx} = \frac{R}{sin(\pi -2x)}$

                                       $\frac{d_{2}}{sinx} = \frac{R}{sin(2x)}$

                                       $\frac{d_{2}}{sinx} = \frac{R}{2sinxcosx}$

                                       $d_{2} = \frac{R}{2cosx}$

                                       $d_{2} = \frac{R}{2cos(37deg)}$

                                       $d_{2} = \frac{5R}{8}$

Now,                               $d_{1}= R - d_{2}$

                                       $d_{1}= R - \frac{5R}{8}$

                                       $d_{1}= \frac{3R}{8}$

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