in the given figure a rectangle tin foil of size 22 CM by 16 cm is wrapped around to form a cylinder of height 16 cm find the volume of the cylinder
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height=16cm
circumference of base=22cm
implies that radius of base=22×7/22×1/2
=3.5cm
Volume of cylinder=pi× r²×h
=22/7×3.5×3.5×16
Volume=616cm³
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Answer:
V = 616 cm³
Step-by-step explanation:
Since the cylinder in wrapped around through the length, the circumference of the down circle will be equal to 22cm
2πr = 22cm
2×22r/7 = 22cm
r = 7/2 cm
Height of cylinder = 16 cm, Hence vol of cylinder is given by,
V = πr²h
V = 22×(7/2)²16/7
V = 22×7×16/4
V = 616 cm³
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