Question

15. If Bhavesh had walked 1 kmph faster, he would have taken 10 minutes less to walk 2 kilometers. What is Bhavesh's
speed of walking?
(a) 1 kmph
(b) 2 kmph
(C) 3 kmph
(d) 6 kmph
​

Answer 1

Answer:

c. 3 km/hr

Step-by-step explanation:

Let the walking speed be x.

Distance is 2 km

Time taken = 2/x

In the second case, speed is x + 1.

Time taken = 2/(x + 1)

This time is 1/6 more than the previous time.

2/(x + 1) = 2/x + 1/6

2/(x + 1) = (12 + x)/6x

12x = (12 + x)(x + 1)

12x = 12x + x^2 + 12 + x

x^2 + x + 12 = 0

x^2 + 4x - 3x + 12 = 0

x(x + 4) - 3(x + 4) = 0

(x + 4)(x - 3) = 0

x = 3 (x cannot be -4, as it is speed)

Therefore the rate of walking is 3 km/h.

Answer 2

Answer:

option C 3kmph

Step-by-step explanation:

can be solve using 2 methods

1st method by option substitution

2nd method by assuming speed

lets assume orginal speed be s

now as distance is common we can equate both speed

so,

s/s+1=t-10/60/t......60 for minutes to hour

and s=2/t

by dividing both equation we can find t and substituting we can get speed