15) If the first two terms of an AP are -3 and 4, then what is the 21st term of this AP?
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Step-by-step explanation:
Given in an AP
First term- t1= a = -3
Second term-t2=4
So common difference d =t2-t1
d= 4-(-3)
d=4+3
d=7
So We have to find the 21st term of AP So n= 21
So t21=?
So we have tn= a+(n-1) d
t21= -3+(21-1)7
t21= -3+140
t21= 137
So the 21st term of the given AP will be 137
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