15.
If the straight line, 3x + 2y - 12 = 0 is perpendicular to the line passing through the
points (4. 13 ) and (7, b) then B equals ...
2) 5
3) - 15
4) 15
The perpendicular distance from (1, 1) to the line 3x + 4y + 8 = 0 is
16.
Answers
Answer:
ME NAHI BATAUNGA
Step-by-step explanation:
I CANT EXPLAIN
Answer:
the given lines are perpendicular and as AB = AC , Therefore △ ABC is art . angled isosceles . Hence the line BC through ( 1 , 2) will make an angles of ±45
∘
with the given lines . Its equations is y - 2 = m (x - 1) where m = 1 / 7 and -7 as in .Hence the possible equations are 7x + y - 9 = 0 and x - 7y + 13 = 0
Alt :
The two lines will be parallel to bisectors of angle between given lines and they pass through ( 1, 2)
∴ y - 2 = m ( x - 1)
where m is slope of any of bisectors given by
5
3x+4y−5
=±
5
4x−3y−15
or x - 7y + 13 = 0 or 7x + y - 20 = 0
∴ m = 1 / 7 or - 7
putting in (1) , the required lines are 7x + y - 9 = 0
and x - 7y + 13 = 0 as found above