Question

15. In an election, there were two candidates A and B. The total number of voters in th
constituency was 60000 and 80% of the total votes were polled. If 60% of the polled vor
were cast in favour of A how many votes were received by B?​

Answer 1

Answer:

19,200Votes

Step-by-step explanation:

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Answer 2

Answer:

Total votes polled =

$80\% \times 60000 = \frac{80}{100} \times 60000 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 48000$

Votes received by A

$= 60\% \times 48000 = \frac{60}{100} \times 48000 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 28800$

Thus,

Votes received by B

$= 48000 - 28800 = 19200$

Step-by-step explanation:

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