15. In fig. ABCD; AB = AD and AC is the bisector of
BC = DC
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IN TRIANGLE ABC AND ADC
WE HAVE
AB =AD (GIVEN)
AC =AC. (COMMON )
BC =CD (GIVEN)
HENCE TRIANGLE ABC AND TRIANGLE ADC ARE CONGRUENT
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Given=
AD=AB
BC=DC
To proof=
ABC is congruent to ADC
Proof =
AD=AB (GIVEN)
BC=DC(GIVEN)
AC=AC(COMMON)
By SSS congruence property we can say that
ABC is congruent to ADC
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