Question

15. In the given figure, ABCD is a
parallelogram. If angleA = 50° and anglrCBD = 70°,
find angleABD and angleBDC.​

Answer 1

Answer:

first do angle sum property of triangle and then we found that angleABD=ANGLE BDC = 60degree

Answer 2

Answer:

angel A = angel C (because ||gm properties)

therefore angle C =50°

triangle sum = 180

b + c + d = 180

angle d = 60

angle b = d ( alternate interior angel)

d= 70

similer angle b= 60

angel BDC = 60

and angle ABD = 60

hence proved

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