15.
In triangle ABC, ZB=90°, AB = 3 centimetres, cosA=3/5
(a)
What is the length of AC ?
(b) Find sinA.
Answers
Answered by
5
Answer:
From figure: △ABCis a right angled triangle
AC
2
=BC
2
+AB
2
AC
2
=(5)
2
+(12)
2
AC
2
=25+144
AC
2
=169=(13)
2
or AC=13
Now from figure,
i.cosA=
AC
AB
=
13
12
ii.cscA=
BC
AC
=
5
13
iii.cosC=
AC
BC
=
13
5
iv.cscC=
AB
AC
=
12
13
Step-by-step explanation:
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