Question

15 is their LCM. The
Prime factorisation of 90 is 90 = 2 x 3 x 3 x 5.
We see that prime factors 2 and 5 are not in pairs. Therefore 90 is not a pun
In order to get a perfect square, each factor of 90 must be paired. So we ne
make pairs of 2 and 5. Therefore, 90 should be multiplied by 2 x 5,i.e., 10.
1. What could be the possible 'one's' digits of the square root of each of the follow
2. Without doing any calculation, find the numbers which are surely not perfect sque
1.1
square.
numbers?
(1) 9801
Hence, the required square number is 90 x 10 = 900.
EXERCISE 6.3
(II) 998001
(iv) 657666
() 99856
(III) 408
(iv) 441
(1) 257
(iv) 4096
(viii) 9216
(1) 153
3. Find the square roots of 100 and 169 by the method of repeated subtraction
4. Find the square roots of the following numbers by the Prime Factorisation Med
(1) 729
() 400
(1) 1764
(V) 7744
(vi) 9604
(vii) 5929
(ix) 529
(x) 8100
5. For each of the following numbers, find the smallest whole number by which it sho
be multiplied so as to get a perfect square number. Also find the square root of
square number so obtained.
(1) 252
(1) 180
( 1008
(iv) 2028
(v) 1458
(vi) 768
6. For each of the following numbers, find the smallest whole number by which it sho
be divided so as to get a perfect square. Also find the square root of the
number so obtained.
Squ
(1) 252
(1) 2925
(i396
(V) 2800
(iv) 2645
(vi) 1620
7. The students of Class VIII of a school donated * 2401 in all, for Prime Minister
National Relief Fund. Each student donated as many rupees as the number of stude
in the class. Find the number of students in the class.​

Answer 1

Answer:

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